16x^2+30x+4=18

Solution for 16x^2+30x+4=18 equation:

16x^2+30x+4=18

We move all terms to the left:

16x^2+30x+4-(18)=0

We add all the numbers together, and all the variables

16x^2+30x-14=0

a = 16; b = 30; c = -14;
Δ = b2-4ac
Δ = 302-4·16·(-14)
Δ = 1796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1796}=\sqrt{4*449}=\sqrt{4}*\sqrt{449}=2\sqrt{449}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{449}}{2*16}=\frac{-30-2\sqrt{449}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{449}}{2*16}=\frac{-30+2\sqrt{449}}{32}
$